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Minimize Z= 3x+y, subject to constriant...

Minimize Z= 3x+y, subject to constriants
` 2x +3y le 6, x +y ge 1, x ge 0 , y ge 0` Then

A

x = 1, y = 1

B

x = 0, y = 1

C

x = 1, y = 0

D

x = - 1, y = - 1

Text Solution

Verified by Experts

The correct Answer is:
B
Feasible region is ABDCA and Z = 3x + Y

Now at A (1,0) Z=3
at B(3,0) Z =9
at B(3,0) Z=9
at C(0,1) Z=1 (Minimum) ,
and at D(0,2) Z =2
It is clear that minimum vlaue of Z is 1 at (0,1) .So X=0 y=1
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