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y=cot^(-1)((1+15x^(2))/(2x)) find dy/dx...

y=`cot^(-1)((1+15x^(2))/(2x))` find dy/dx

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To find the derivative \( \frac{dy}{dx} \) for the function \( y = \cot^{-1}\left(\frac{1 + 15x^2}{2x}\right) \), we can follow these steps: ### Step 1: Rewrite the function using the identity for cotangent We know that: \[ \cot^{-1}(x) = \tan^{-1}\left(\frac{1}{x}\right) \] Thus, we can rewrite \( y \) as: ...
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