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If log(10)((x^(3)-y^(3))/(x^(3)+y^(3)))=...

If `log_(10)((x^(3)-y^(3))/(x^(3)+y^(3)))=2`, then `(dy)/(dx)=`

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`log_(10)((x^(3)-y^(3))/(x^(3)+y^(3)))=2`
`therefore (x^(3)-y^(3))/(x^(3)+y^(3))=10^(2)=100`
`thereforex^(3)-y^(3)=100x^(3)+100y^(3)`
`therefore101y^(3)=-99x^(3) thereforey^(3)=(-99)/(101)x^(3)`
Differentiating both sides w.r.t. x, we get,
`3y^(2)(dy)/(dx)=(-99)/(101)xx3x^(2)`
`therefore (dy)/(dx)=-(99x^(2))/(101y^(2))`
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Knowledge Check

  • If x^(y) =3^(x-y),then (dy)/(dx)=

    A
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    B
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  • If y^(3) - 3y^(2) x=x^(3) +3x^(2) y,then (dy)/(dx)=

    A
    `(x^(2) +2xy +y^(2))/( y^(2)- 2xy -x^(2))`
    B
    `(x^(2) +2xy +y^(2))/( y^(2)+ 2xy -x^(2))`
    C
    `(x^(2) -2xy -y^(2))/( y^(2)+ 2xy +x^(2))`
    D
    `(x^(2) + 2xy -y^(2))/( y^(2)+ 2xy +x^(2))`
  • If y=(x cot^(3)x)^(3/2) , then (dy)/(dx)=

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    `3/2(x cot^(2) x)^(1/2) (cot^(3)x - 3x cot^(2) x "cosec"^(2)x)`
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    C
    `3/2(x cot^(3)x)^(1/3)(cot^(3)x - 3x "cosec"^(2)x)`
    D
    `3/2(x cot^(3) x)^(3/2) (cot^(3)x - 3x "cosec"^(2)x)`
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