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(sec^(2)x-7)/(sin^(7)x)...

`(sec^(2)x-7)/(sin^(7)x)`

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To solve the integral \(\int \frac{\sec^2 x - 7}{\sin^7 x} \, dx\), we can break it down into two separate integrals: \[ \int \frac{\sec^2 x}{\sin^7 x} \, dx - 7 \int \frac{1}{\sin^7 x} \, dx \] ### Step 1: Rewrite the first integral We can rewrite \(\sec^2 x\) in terms of sine and cosine: ...
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