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Calculate the period of revolution of a ...

Calculate the period of revolution of a satellite orbiting above the surface of the Earth at a distance equal to 9 times the radius of the Earth.

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Data : G= ` 6.67 xx10^(-11) N.m^(2)//kg^(2) , h = 9R, M = 6 xx 10^(24) ` kg
` R = 6.4 xx 10^(6)` m
R + h = 10R = ` 10xx 6.4 xx 10^(6) = 6.4 xx 10^(7)` m
The period of revolution of the satellite.
`T = 2pi sqrt(((R+h)^(3))/(GM))`
` = 2xx 3.142 xx sqrt(((6.4xx10^(7))^(3))/(6.67xx 10^(-11) xx 6xx10^(24)))`
= `1.608 xx 10^(5)` seconds
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