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How much above the surface of the earth does the acceleration due to gravity reduce by `36%` of its value on the surface of the earth.

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Data : ` g_(h)//g = 64% , = 0.64 , R_(E) = 6400 Km`
` g_(h) =g(R_(E)/(R_(E)+h))^(2)`
` R_(E)/(R_(E) +h) = sqrt(g_(h)/g) = sqrt(0.64) = 0.8`
` (R_(E)+h)/(R_(E)) = 10/8 = 5/4 " " therefore 4R_(E) + 4h = 5R_(E)`
The altitude , ` h = R_(E)/4 = (6400)/4 = 1600 km`
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