Home
Class 12
PHYSICS
The equation of linear SHM is x= 10sin (...

The equation of linear SHM is x= 10`sin ( 4pi t + pi/6)` cm. Find the period and maximum speed of the motion.

Text Solution

Verified by Experts

Data : x = ` 10 sin ( 4 pit+ pi/6) ` cm ltbr In the usual notation, the expression for displacement of a particle in linear SHM is
` x = A sin (omega t+ prop)`
Comparing this equation with the given equation , we get,
` A =10 cm, m omega = 4 pi "rad/s" prop = pi/6 " rad"`
Therefore, (i) The period , ` T= (2pi)/omega = (2pi)/(4pi) = 0.5 s `
(ii) The maximum speed,` v_(max) = omegaA= (4 pi") (0.1)`
= ` 0.4 xx 3.142`
= 1.2568 m/s
Promotional Banner

Topper's Solved these Questions

  • SOLVED PROBLEMS - I

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise ELASTICITY|26 Videos
  • SOLVED PROBLEMS - I

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise WAVE MOTION|11 Videos
  • SOLVED PROBLEMS - I

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise GRAVITATION|9 Videos
  • SHORT ANSWER QUESTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignments|3 Videos
  • SOLVED PROBLEMS-II

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignments|5 Videos

Similar Questions

Explore conceptually related problems

Equation of SHM is x = 10 sin 10 pi t . Then the time period is, x is in cm and t is in sec

A body is executing SHM according to the equation : y = 14 sin( 100 pi t + (pi/6)) cm. Find its maximum speed.

The equation of motion of a body is S.H.M. IS X=4 sin(pit+pi/3) . The frequency, per minute, of the motion is

A body is executing SHM according to the equation : y = 14 sin( 100 pi t + (pi/6)) cm. Find its maximum acceleration.

The equation of motion of a body in S.H.M. is x=4 sin(pit+pi/3) . The acceleration, in cm//S62 , at the end of 4 s will be

period of sin(2 pi t+(pi)/(6))

The displacement y (in cm ) produced by a simple harmonic wave is y=(10)/(pi) sin (2000 pi t -(pi x)/(17)) . The periodic time and maximum velocity of the particles in the medium will respectively be

A simple harmonic motion is represented by : y = 5(sin 3pi t + sqrt(3) cos 3pi t)cm The amplitude and time period of the motion are :

Displacement of a particle executing SHM s x= 10 ( cos pi t + sin pi t) . Its maximum speed is

The equation of a prticle executing simple harmonic motion is x=(5m)sin[(pis^-1)t+pi/3]. Write down the amplitude time period and maximum speed. Also find the velocity at t=1s.

NAVNEET PUBLICATION - MAHARASHTRA BOARD-SOLVED PROBLEMS - I -ROTATIONAL MOTION
  1. A solid cylinder, of mass 2 kg and radius 0.1 m, rolls down an incline...

    Text Solution

    |

  2. A solid sphere of radius 25 cm and mass 25 kg rotates about an axis th...

    Text Solution

    |

  3. Two wheels, each of moment of intertia 4 kg. m^(2), rotate side by si...

    Text Solution

    |

  4. A unifrom horizontal disc is freely rotating about a vertical axis thr...

    Text Solution

    |

  5. A ballet dancer spins about a vertical axis at 100 rpm which arms outs...

    Text Solution

    |

  6. The equation of linear SHM is x= 10sin ( 4pi t + pi/6) cm. Find the p...

    Text Solution

    |

  7. Find the maximum velcoity and maximum acceleration of a particle perfo...

    Text Solution

    |

  8. A particle performs SHM of ampiltude 10 cm. Its maximum velcoity durin...

    Text Solution

    |

  9. The diameter of the reference circle for a particle performing linear ...

    Text Solution

    |

  10. A load of mass 100 gm increases the length of wire by 10 cm. If the sy...

    Text Solution

    |

  11. A particle performs a linear S.H.M. of period 3 second. The time taken...

    Text Solution

    |

  12. A particle performs linear SHM of period 12 seconds and amplitude 8 cm...

    Text Solution

    |

  13. A particle in linear SHM has speeds 4 cm/s and 3 cm/s when its displac...

    Text Solution

    |

  14. The potential energy of a partical is SHM is 2 xx 10^(-4) J at the e...

    Text Solution

    |

  15. The total energy of a particle of mass 0.1 kg performing SHM is 0.2 J...

    Text Solution

    |

  16. A particle of mass 10 g is performing SHM. Its kinetic energies are 4....

    Text Solution

    |

  17. A particle is performing SHM with amplitude 2 cm. At what distance fro...

    Text Solution

    |

  18. A body of mass 0.1 kg performing linear SHM experiences a restoring f...

    Text Solution

    |

  19. An SHM is given by the equation x = 8 sin (4 pi t) + 6 cos (4pit)] cm...

    Text Solution

    |

  20. Define linear simple harmonic motion. Assuming the expression for disp...

    Text Solution

    |