The diameter of the reference circle for a particle performing linear SHM is 10 cm. If the reference particle performs UCM with period `2pi` seconds, what is the maximum acceleration of the particle in linear SHM ?

Explanation

The period of the SHM, T = the period of UCM of the reference particle,= ` 2pi`s , Also, the ampliitude, of the SHM. A = the radius of the reference circle = 5 m,
The maximum acceleration
` a_(max) = omega^(2)A = ((2pi)/T)^(2) A = ((2pi)/(2pi))^(2) xx 5 xx 10^(-2) = 5 xx 10^(2) m//s^(2)`