Define linear simple harmonic motion. Assuming the expression for displacement of a particle starting from extreme position, explain graphically the varition of velocity and acceleration w.r.t. time.
A clock reagulated by seconds pendulum, keeps correct time. During summer, length of pendulum increases to 1.005 m. How much will the clock gain or loose in one day `(g=9.8m//s^(2)andpi=3.142)`.

Explanation

Data : L = 1.005 m , g= ` 9.8 m//s^(2)`
` T= 2pi sqrt(L/g)`
` = 2xx 3.142 xx sqrt((1.005)/(9.8))`
` = 6.284 sqrt(1.005/9.8) = 2.012 s , " " therefore T= 2.012 s`
The period of a seconds pendulum is 2 seconds. Hence, the given pendulum will lose 2.012-2 = 0.012 s in 2.012 s during summer. Time lost in 24 hours.
`= (24 xx 3600 xx 0.012)/(2.012) s= 515.3` s