The surface tension of water at ` 0^(@) C` is 75.5 dyn/cm. Calculate the surface tension of water at ` 25^(@)C` .

Explanation

Data : ` T _(0) = 75.5 dyn//,cm prop = 0.0027 // ^(@)C , theta = 25^(@) C`
` T = T_(0) (1 - proptheta) = 75.5 ( 1- 0.0027 xx 25)`
= ` 75.5 (1- 0.0675) = 75.5 xx 0.9325`
70 . 39 dyn/cm
This is the surface tension of water at `25^(@) C`