A pipe which is opne at both ends is 47 cm long and has an inner diameter 5 cm. If the speed of sound in air is 348 m/s, calculate the fundamental frequency of air column in that pipe.

Explanation

The fundamental frequency of the air column is
` n= v/(2(L+ 0.6d))`
The frequency of the third overtone = 4n
`= (4v)/(2 (L + 0.6d)) = ( 4xx 348)/(2(0.47 + 0.6 xx 0.05)) = (2 xx 348)/(0.47 + 0.03)`
` = (2 xx 348)/(0.5) = 4 xx 348 = 1392 Hz`