A stretched wire emits a fundamental note of frequency 256Hz. Keeping the stretching force constant and reducing the length of the wire by 10cm, frequency becomes 320Hz. Calculate original length of the wire.

Explanation

`n prop 1/L " " n_(2)/n_(1) = L_(1)/L_(2)`
` 320/256 = L_(1)/(L_(1) -10) " " therefore L_(1)/10 = 320/(320 - 256)`
`L_(1) = 10 xx 320/64 = 10x x 5 = 50 `cm
This is the original length of the wire.