A battery of emf 2V and internal resistance `0.5(Omega)`is connected across a resistance in 1 second?

Explanation

To solve the problem step by step, we will determine how many electrons cross through a cross-section of the resistance in one second when a battery of emf 2V and internal resistance 0.5Ω is connected across a resistance of 9.5Ω.

### Step 1: Calculate the Total Resistance in the Circuit
The total resistance (R_total) in the circuit is the sum of the internal resistance of the battery (r) and the external resistance (R).

\[ R_{\text{total}} = r + R = 0.5 \, \Omega + 9.5 \, \Omega = 10 \, \Omega \]
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