Find the equivalent resistance between the point a and b of the network shown in figure.

Options

A. 3
B. 2
C. 1
D. 5

Answer

A

Explanation

The two resistors `4Omega`and `2Omega`at the right end are joined in series and may be replaced by a single resistor of `6Omega`is connected with the adjacent `3Omega`resistor in parallel. The equivalent resistance of these two is
`(6(Omega)xx3(Omega))/(6(Omega)+3(Omega))=2(Omega)`.
This is connected in series with the adjacent `4(Omega) resistors giving an equivalent resistance of `6(Omega)`which is connected in parallel with the 3(Omega) resistor. Their equivalent resistance is `2(Omega)`which is connected in series with the first `4(Omega)`resistor from left. Thus ,the wquivalent risistance between a and b is `6(Omega)`.