Find the effective resistance between the points A and B in figure.

Explanation

The resistors AF and FE are in series. Their equivalemt resistance is `3(Omega)+3(Omega)=6(Omega).`this is connected din parallel with AE. Their equivalent between A and E is , therefore.
`(6(Omega)xx6(Omega))/(6(Omega)+6(Omega))=3(Omega)`
This 3(Omega) resistance between A and E is in series with ED and the combination is in parallel with AD. Their equivalent is between A and D is again `3(Omega)`
Similarly the equivalent of this `3(Omega),DC and AC is `3(Omega)`. This `3Omega `is in series with CB and the combination is in parallel with AB. The equivalent resistance between A and B is , Therefore,
`(6(Omega)xx3(Omega))/(6(Omega)+3(Omega))=2(Omega).`