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int(1)/(1+cos ax)dx is equal to...

`int(1)/(1+cos ax)dx` is equal to

A

`cot.(ax)/(2)+C`

B

`(1)/(a)tan.(ax)/(2)+C`

C

`(1)/(a)("cosec ax" - cos ax)+C`

D

`(1)/(a)("cosac ax"+cot ax)+C`

Text Solution

Verified by Experts

The correct Answer is:
B
`int(1)/(1+cosax)dx=int(dx)/(2cos^(2)(ax//2))`
`=(1)/(2)intsec^(2)((ax)/(2))dx=(1)/(2).(tan(ax//2))/((a//2))`
`=(1)/(a)tan((ax)/(2))+C`
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