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The integral int(1+x-1/x)e^(x+1/x)dx is ...

The integral `int(1+x-1/x)e^(x+1/x)dx` is equal to

A

`(x+1)e^(x+(1)/(x))+C`

B

`-xe^(x+(1)/(x))+C`

C

`(x-1)e^(x+(1)/(x))+C`

D

`xe^(x+(1)/(x))+C`

Text Solution

Verified by Experts

The correct Answer is:
D

`int(1+x-(1)/(x))e^((x+(1)/(x)))dx`
`=inte^((x+(1)/(x)))dx+intx(1-(1)/(x^(2)))e^((x+(1)/(x)))dx`
On integrating `intx(1-(1)/(x^(2)))e^((x+(1)/(x)))dx` by parts considering
x as first function and `(1-(1)/(x^(2)))e^((x+(1)/(x)))` as second function,
we get
`=inte^((x+(1)/(x)))dx+xe^((x+(1)/(x)))-inte^((x+(1)/(x)))dx`
`=xe^((x+(1)/(x)))+C`
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