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At what height from the surface of earth...

At what height from the surface of earth will the value of g be reduced by `36%` from the value on the surface? Take radius of earth `R = 6400 km`.

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The correct Answer is:
A
`g' = 0.64 g = (g)/((1 + (h)/(R))^(2))`
`:. 1 + (h)/(R) = (5)/(4)`
`h =(R )/(4) = 1600 km`
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