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A body is weighted by a spring balance t...

A body is weighted by a spring balance to be 1.000 kg at the north pole. How much will it weight at the equator. Account for the earth\'s rotation only.

Text Solution

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At equator, `g' = g - R omega^(2)`
`= (9.8)^(2) - (6400 xx 10^(3)) ((2 pi)/(24 xx 3600))^(2)`
`= 9.766 m//s^(2)`
Now, `mg = 1000`
`:. M = (1000)/(g)`
`w' = mg' = (1000) ((g')/(g))`
`= ((1000)(9.766))/((9.8)) = 997 N`
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