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At what rate should the earth rotate so ...

At what rate should the earth rotate so that the apparent g at the equator becomes zero? What will be the length of the day in this situation?

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The correct Answer is:
A, B, C, D
`g' = g - R omega^(2)`
`:. 0 = g - R omega^(2)`
`:. Omega = sqrt((g)/(R)) = sqrt ((9.8)/(6400 xx 1000))`
`= 1.237 xx 10^(-3) rad//s` and `T = (2 pi)/(omega)`
By putting the value of `omega`, we get
`T ~~ 84.6 min`
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