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For a particle undergoing simple harmoni...

For a particle undergoing simple harmonic motion, the velocity is plotted against displacement. The curve will be

A

a straight line

B

a parabola

C

a circle

D

an ellipse

Text Solution

Verified by Experts

The correct Answer is:
D

`v = omega sqrt(A^(2)) - (x^(2))`
`:. (v^(2))/(omega^(2)) + (x^(2))/(1)^(2) = A^(2)`
Hence, `v - x` graph is an ellipse.
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