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Two simple harmonic motions are given by...

Two simple harmonic motions are given by `y_(1) = a sin [((pi)/(2))t + phi]` and `y_(2) = b sin [((2pi)/( 3))t + phi]`. The phase difference between these after `1 s` is

A

zero

B

`pi//2`

C

`pi//4`

D

`pi//6`

Text Solution

Verified by Experts

The correct Answer is:
D
At `t = 1 s`
`phi_(1) = (pi)/(2) + phi`
and `phi_(2) = (2pi)/(3) + phi`
`:. Delta phi = phi_(2) - phi_(1) = (pi)/(6)`
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