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Two bodies P and Q of equal masses are s...

Two bodies `P` and `Q` of equal masses are suspended from two separate massless springs of force constants `k_(1)` and `k_(2)` respectively. If the two bodies oscillate vertically such that their maximum velocities are equal. The ratio of the amplitude of `P` to that of `Q` is

A

`sqrt((k_(1))/(k_(2))`

B

`(k_(1))/(k_(2))`

C

`sqrt((k_(2))/(k_(1)))`

D

`(k_(2))/(k_(1))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the given conditions and apply the concepts of simple harmonic motion (SHM). ### Step 1: Understanding the given information We have two bodies, P and Q, each with equal masses (let's denote the mass as \( m \)). They are suspended from springs with spring constants \( k_1 \) and \( k_2 \), respectively. Both bodies oscillate vertically and have the same maximum velocities. ### Step 2: Relating maximum velocity to amplitude In SHM, the maximum velocity (\( V_{\text{max}} \)) of a mass-spring system is given by the formula: \[ V_{\text{max}} = \omega A \] where: - \( \omega \) is the angular frequency, - \( A \) is the amplitude of oscillation. ### Step 3: Expressing angular frequency The angular frequency \( \omega \) for a mass-spring system is given by: \[ \omega = \sqrt{\frac{k}{m}} \] where \( k \) is the spring constant and \( m \) is the mass. ### Step 4: Setting up the equations For body P: \[ V_{1, \text{max}} = \omega_1 A_1 = \sqrt{\frac{k_1}{m}} A_1 \] For body Q: \[ V_{2, \text{max}} = \omega_2 A_2 = \sqrt{\frac{k_2}{m}} A_2 \] Since \( V_{1, \text{max}} = V_{2, \text{max}} \), we can equate the two expressions: \[ \sqrt{\frac{k_1}{m}} A_1 = \sqrt{\frac{k_2}{m}} A_2 \] ### Step 5: Simplifying the equation We can cancel \( m \) from both sides: \[ \sqrt{k_1} A_1 = \sqrt{k_2} A_2 \] ### Step 6: Finding the ratio of amplitudes Rearranging the equation gives us: \[ \frac{A_1}{A_2} = \frac{\sqrt{k_2}}{\sqrt{k_1}} \] Thus, the ratio of the amplitudes of P to Q is: \[ \frac{A_1}{A_2} = \sqrt{\frac{k_2}{k_1}} \] ### Final Answer The ratio of the amplitude of P to that of Q is: \[ \frac{A_1}{A_2} = \sqrt{\frac{k_2}{k_1}} \] ---

To solve the problem step by step, we need to analyze the given conditions and apply the concepts of simple harmonic motion (SHM). ### Step 1: Understanding the given information We have two bodies, P and Q, each with equal masses (let's denote the mass as \( m \)). They are suspended from springs with spring constants \( k_1 \) and \( k_2 \), respectively. Both bodies oscillate vertically and have the same maximum velocities. ### Step 2: Relating maximum velocity to amplitude In SHM, the maximum velocity (\( V_{\text{max}} \)) of a mass-spring system is given by the formula: \[ ...
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