The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)) + pi^(2)x = 0`, where `x` is displacement (in m) from mean position. The frequency of oscillation is (in Hz)

Options

A. `1//2`
B. `2`
C. `5sqrt(10)`
D. `1//5 sqrt(10)`

Answer

A

Explanation

`(d^(2)x)/(dt^(2)) = - pi^(2)x`
Comparing with `(d^(2)x)/(dt^(2)) = - omega^(2)x`
We have, `omega = pi`
`:. 2pif = pi`
`f = (1)/(2) Hz`.