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The equation of motion of a particle of ...

The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)) + pi^(2)x = 0`, where `x` is displacement (in m) from mean position. The frequency of oscillation is (in Hz)

A

`1//2`

B

`2`

C

`5sqrt(10)`

D

`1//5 sqrt(10)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(d^(2)x)/(dt^(2)) = - pi^(2)x`
Comparing with `(d^(2)x)/(dt^(2)) = - omega^(2)x`
We have, `omega = pi`
`:. 2pif = pi`
`f = (1)/(2) Hz`.
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Knowledge Check

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