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A particle is attached to a vertical spr...

A particle is attached to a vertical spring and is pulled down a distance `4 cm` below its equilibrium and is released from rest. The initial upward acceleration is `0.5ms^(-2)`. The angular frequency of oscillation is

A

`3.53 rad//s`

B

`0.28 rad//s`

C

`1.25 rad//s`

D

`0.08 rad//s`

Text Solution

Verified by Experts

The correct Answer is:
A
`T = 2pi sqrt|(x)/(a)|`
`:. omega = (2pi)/(T) = sqrt|(x)/(a)| = sqrt((0.5)/(4xx10^(-2)))`
` = 3.53 rad//s`
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