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A simple pendulum with a solid metal bob...

A simple pendulum with a solid metal bob has a period `T`. What will be the period of the same pendulum if it is made to oscillate in a non - viscous liquid of density one - tenth of the of the metal of the bob ?

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The correct Answer is:
A

`g_(e) = g -("Upthrust")/("mass")`
`= g - (V(delta//10)g)/(Vdelta) = (9)/(10)g`
`T' = 2pi sqrt((l)/(g_(e))) = 2pi sqrt((10)/(9))((l)/(g))`
`= (sqrt(10)/(9))T `
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