A simple pendulum of length `l` and mass `m` is suspended in a car that is moving with constant speed `v` around a circle of radius `r`. Find the period of oscillation and equilibrium position of the pendulum.

Answer

A, B, C, D

Explanation

` g_(e) = sqrt (((v^(2))/( r))^(2)) + g^(2)`
`T = 2pi sqrt ((g)/(g_(e))) rArr theta = tan^(-1)((v^(2))/(rg))`