A body makes angular simple harmonic motion of amplitude `pi//10rad` and time period `0.05s`. If the body is at a displacement `theta = pi//10 rad` at `t = 0`, write the equation giving angular displacement as a function of time.

Answer

A, C, D

Explanation

`omega = (2pi)/(T) = (2pi)/(0.05) = (40pi) rad//s`
Since, the body starts from the extreme position, we can write
`theta = theta_(0) cos omega t`
or `theta = ((pi)/(10)) cos 40pit`