A body of mass `200 g` oscillates about a horizontal axis at a distance of `20 cm` from its centre of gravity . If the length of the equivalent simple pendulum is `35cm`, find its moment of inertia about the point of suspension.

Answer

A, B, C, D

Explanation

`2pi sqrt((l)/(g)) = 2pi sqrt((I)/(mgl'))`
`:. l = (I)/(ml')`
or `I = (m)(l)(l')`
` = (200)(20)(35)`
` = 1.4 xx 10^(5) g - cm^(2)`