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The period of a particle in SHM is 8 s. ...

The period of a particle in SHM is `8 s`. At `t = 0` it is in its equilibrium position.
(a) Compare the distance travelled in the first `4s` and the second `4s`.
(b) Compare the distance travelled in the first `2s` and the second `2s`.

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The correct Answer is:
A, B
(a) Distance travelled in first `4 s`
`= OP + PO = A + A = 2 A`
Distance travelled in next `4 s`
`= OQ + QO = A + A = 2A`
Two distances are equal.

(b) Distance travelled in first `2 s = OP = A` and
distance travelled in next `2 s = PO = A`
Again the two distance are same.
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