A seconds pendulum is suspended from the ceiling of a trolley moving horizontally with an acceleration of `4 m//s^(2)` . Its period of oscillation is

Options

A. `1.90s`
B. `1.70 s`
C. `2.30 s`
D. `1.40 s`

Answer

A

Explanation

`g_(e) = sqrt(g^(2) + a^(2)) = sqrt((10)^(2) + (4)^(2))`
`= 10.77 m//s^(2)`
`T = 2pi sqrt((l)/(g_(e)) = 2pi sqrt((1)/(10.77))`
`= 1.90 s`