A solid cube of side a and density `rho_(0)` floats on the surface of a liquid of density `rho`. If the cube is slightly pushed downward, then it oscillates simple harmonically with a period of

Options

A. `2pisqrt((rho_(0))/(rho)(a)/(g))`
B. `2pi sqrt((rho)/(rho_(0))(a)/(g))`
C. `2pi sqrt ((a)/((1 - (rho)/(rho_(0)))g`
D. `2pi sqrt ((a)/((1 + (rho)/(rho_(0)))g`

Answer

A

Explanation

`T = 2pi sqrt((m)/(k))`
Here `m = (rho_(0))(a^(3))`
and `K = rho_(l) A g = rhoa^(2)g`
`:. T = 2pi sqrt ((rho_(0)a)/(rhog))` .