Graph for specific heat at constant volume for a monoatomic gas

Options

A.
B.
C.
D.

Answer

C

Explanation

According to first law of thermodynamics
`DeltaQ=DeltaU+PDeltaV`
If `DeltaQ` is absorbed at constant volume, `DeltaV=0`
`C_(V)=((DeltaQ)/(DeltaT))_(V)=((DeltaU)/(DeltaT))_(V)=(DeltaU)/(DeltaT)`
for an ideal monoatomic gas
`(DeltaU)/(DeltaT)=3/2R, C_V=3/2R`