x के सापेक्ष अवकलन कीजिए ।
`cos(logx+e^(x))`

Explanation

माना `y=cos(logx+e^(x))`
`rArr" "(dy)/(dx)=(d)/(dx)cos(logx+e^(x))`
`=-sin(logx+e^(x))(d)/(dx)(logx+e^(x))`
`=-sin(logx+e^(x))((1)/(x)+e^(x))`
`=(-sin(logx+e^(x))(1+x.e^(x)))/(x)`