`H_2SO` acts as
(i). An acid.
(ii) An oxidising agent
A dehydrating agent
Select equations from rthe following which explain each type
(a) `5H_2SO_4("conc")+4Znto4Zn^(2+)+H_2S+4SO_4^(2-)+4H_2O`
(b) `H_2SO_4("dil")+ZntoZn^(2+)+H_2+SO_4^(2-)`
(c) `C_(6)H_(12)O_(6) overset(H_(2)SO_(4)("conc"))to6C +6H_(2)O`
(d) `H_(2)SO_(4)("dil")+ZnCO_(3) rarr Zn^(2+) +CO_(2)+SO_(4)^(2-)+H_(2)O`.

Explanation

(a) `H_2SO_4` acts as oxidising agent, in which `SO_4^(2-)` is reduced to `S^(2-)` (sulphide ion)
`8e^(-)+ underset underset(x=6)(x-8=-2)(SO_(4)^(2-)) rarr underset(x=-2)(S^(2-))`
(b) `H_2SO_4` acts as an acid and an oxidising agent. All strong acids can liberate `H_2` with an active metal such as Zn, unless another part of the molecule is more easily reduced
`ZntoZn^(2+)+2e^(-)`
`2H^(o+)+2e^(-)toH_2`
(c) `H_(2)SO_(4)` acts as a dehydrating agent since it removes `H_(2)O` from `C_(6)H_(12)O_(6)`
(d) `H_(2)SO_(4)` acts as an acid since `Zn^(2+)` in `ZnCO_(3)` and `SO_(4)^(2-)` in `H_(2)SO_(4)` does not change, only `H^(oplus)` ions in `H_(2)SO_(4)` reacts with `CO_(3)^(2-)` to give `CO_(2)` and `H_(2)O`.