What volume of 0.1 M `KMnO_4` is required to oxidise 100 " mL of " 0.3 `FeC_2O_4` (ferrous oxalate) in acidic medium?

Explanation

`{:(Fe^(2+)toFe^(3+)+e^(-)),(Cr_2O_4^(2-)to2CO_2+2e^(-)):}]`n-factor`=3`
`5e^(-)+MnO_4^(ɵ)toMn^(2+)(n=5)`
`1mEq-=1mEq`
`N_1V_1(mL)-=N_2V_2(mL)`
`0.1xx5` (n-factor )`xxV_1-=0.3xx3` (n-factor)`xx100mL`
`V_1=(0.3xx3xx100)/(0.1xx5)=`180mL`