How many moles of `HgI_4^(2-)` will be formed when 2 " mol of "`Hg^(2+)` and 2 mol `I^(ɵ)` react according to the following equation?
`Hg^(2+)+4I^(ɵ)toHgI^(2-)`
(a). 1 mol
(b). 0.5 mol
(c). 0.25 mol
(d). 2 mol

Explanation

(b). `Hg^(2+)-=4I^(ɵ)-=HgI_4^(2-)`
`1 mol-=4mol-=1mol`
`(1)/(4)mol-=(4)/(4)mol-=(1)/(4)mol`
`(2)/(4)mol=(4xx2)/(4)mol=(2)/(4)"mol" implies0.5mol`