1.84 g of `CaCO_3` and `MgCO_3` were treated with `50 mL` of 0.8 HCl solution. Calculate the percentage of `CaCO_3` and `MgCO_3`.

Explanation

To solve the problem of determining the percentage of `CaCO3` and `MgCO3` in a mixture weighing 1.84 g that reacts with 50 mL of 0.8 HCl solution, we can follow these steps:

### Step 1: Define Variables
Let:
- \( x \) = mass of \( CaCO3 \) in grams
- \( (1.84 - x) \) = mass of \( MgCO3 \) in grams

### Step 2: Calculate the Molar Masses
...