The neutralisation of a 1.20 g solution of a mixture of `H_2C_2O_4.2H_2O` and `KHC_2O_4.H_2O` and different impurities of a neutral salt consumed 37.80 " mL of " 0.25 N NaOH solution. On the other hand, on titration with `KMnO_4` for 0.40 g of the same substance, 43.10 " mL of " 0.125 N `KMnO_4` was required. Find the percentage composition of the substance being analysed.

Explanation

Let the percentage of `H_2C_2O_4.2H_2O` be `a%` and the percentage of `KHC_2O_4.H_2O` be `b%`
(a). `(1.2)/(100)((a)/(63)+(b)/(146))xx1000=37.80xx25`
(b). `(0.40)/(100)((a)/(63)+(b)/(73))xx1000=43.10xx0.125`
`a=H_2C_2O_4.2H_2O=14.3%`
(b). `=KHC_2O_4.H_2O=81.7%`