In the reaction of Mohr's salt `[FeSO_4(NH_4)_2SO_4.6H_2O]` with oxalate ions in the presence of `H_2O_2` and `H^(o+)` ions, `[Fe(C_2O_4)_3]^(3-)` ion is formed. Calculate the minimum mass of Mohr's salt and `K_2C_2O_4` required to prepare 10 g of `K_3Fe(C_2O_4)_2`.

Explanation

`2Fe^(2+)+6C_2O_4^(2-)+H_2O_2+H^(o+)to2[Fe(C_2O_4)_3]^(3-)+2H_2O`
Molecular weight of Mohr's salt `=392`
Molecular weight of `K_2Fe(C_2O_4)_3=437`
Molecular weight `K_2C_2O_4=166`
`2 " mol of "K_2Fe(C_2O_4)_3=6 mol` of `K_2C_2O_4`.
`(10)/(437) mol` of `K_3Fe(C_2O_4)_3=(6)/(2)xx(10)/(437)xx166g of K_2C_2O_4`
Are required `=11.4 g`
1 mole of `K_3Fe(C_2O_4)_3=` 1 " mol of "Mohr's salt `(Fe^(2+))`
`(10)/(437) mol` of `K_3Fe(C_2O_4)_3=(10)/(437)xx392=8.92g`