Ten millilitre ofa mixture of methane, ethylene, and carbon dioxide was exploded with excess of air: After the explosion, there was contraction of 17 ml and after treatment with `KOH`, there was a further contraction of 14 ml. What was the composition of the mixture?

Explanation

Let the volume of `CH_4` be x mL
Volume of `(CH_2=CH_2)=ymL`
Volume of `CO_2=[10-(x+y)]mL`
(a). `CH_4(g)+2O_2(g)toCO_2(g)+2H_2O(l)`
(b). `CH_2=CH_2(g)+3O_2(g)to2CO_2(g)+H_2O(l)`
Volume of `CO_2` absorbed by `KOH=14mL`
`thereforey=4mL`
Volume of gaseous reactant `=` volume of gaseous production`+`constraction
`x+2x+y+3Y=x+2y+17`
`3x+4y-x-2y=17`
`2x+2y=17`
`2x+2xx4=17`
`2x=9`
`x=4.5mL`
Volume of `CH_4=4.5mL`
Volume of `CH_2=CH_2=4mL`
Volume of `CO_2=10-(4.5+4)=1.5mL`