A gaseous alkane was exploded with oxygen. The volume of `O_(2)` for complete combustion to `CO_(2)` formed was in the ratio of `7:4`. The molecular formula of alkane is:

Explanation

`C_(n)H_(2n+2)+[n+(n+1)/(2)]O_2tonCO_2+(n+1)H_2O(l)`
`("Volume of " O_2 used)/("Volume of " CO_2 formed)=(7)/(4)`
`(n+(n+1)/(2))/(n)=(7)/(4)`
`n=2`
Hence, the alkane is `C_2H_6`