50 " mL of " pure and dry `O_2` was subjected to silent electric discharge and on cooling to the original temperature, the volume of ozonised oxygen was found to be 47 mL The gas was brought into contact with turpentine oil, after absorption of `O_3`, the remaining gas occupied 41 mL volume. What is the molecular formula of ozone?

Explanation

Let a " mL of " `O_2` form `O_(n)`.
`{:[("Before reaction"),("After reaction")]:}_(50-a)mL^(50mL) (2a)/(n)mL`
`V_(O_2)(l eft)=(50-a)implies41=50-a`
Also, `V_(O_3)` (formed) `=47-41=6mL`
`therefore(2a)/(n)=6`
`n=3`
Hence, the molecular formula of ozone is `O_3`