The vapour density of mixture consisting of `NO_2` and `N_2O_4` is 38.3 at `26.7^@C`. Calculate the number of moles of `NO_2` I `100g` of the mixture.

Explanation

Molecular weight of the mixture`=38.3xx2=76.6`
Molecular weight of `NO_2=46 and N_2O_4=92`
Let the number of moles of `NO_2` be x.
Number of moles of `N_2O_4=(100-46x)/(92)`
`x+(100-46x)/(92)=(100)/(76.6)impliesx=0.438mol`