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How many moles of NO2^(ɵ) are oxidised t...

How many moles of `NO_2^(ɵ)` are oxidised to `NO_3^(ɵ)` by 2 " mol of "`MnO_4^(ɵ)` in dilute basic medium?

Text Solution

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In dilute basic medium `MnO_4^(ɵ(` is reduced to `MnO_2`.
`3e^(-)+MnO_4^(ɵ)toMnO_2(n=3)`,
`NO_2^(ɵ)toNO_3^(ɵ)+2e^(-)(n=2)`
`MnO_4^(ɵ)-=NO_2^(ɵ)`
`1Eq-=1Eq`
`(1)/(3)mol-=(1)/(2)mol`
1 " mol of "`MnO_4^(ɵ)-=(3)/(2)" mol of "NO_2^(ɵ)`
2 " mol of "`MnO_4^(ɵ)=3 " mol of "NO_2^(ɵ)`
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