Home
Class 11
CHEMISTRY
30 " mL of " a solution of mixture of Na...

30 " mL of " a solution of mixture of `Na_2CO_3` and `NaHCO_3` required 12 " mL of " 0.05 M `H_2SO_4` using phenolphthalein as indicator. With methyl orange 30 " mL of " the same solution required 40 " mL of " same `H_2SO_4`. Calculate the amount of `Na_2CO_3` and `NaHCO_3` per litre in the mnixture.

Text Solution

Verified by Experts

With phenolphthalein indicator
`m" Eq of "H_(2)SO_(4) used =12xx0.05xx2` (n-factor)
`=1.2`
Let a and b m" Eq of "`NaHCO_(3)` and `Na_(2)CO_(3)`, respectively.
`therefore(b)/(2)=1.2`
With methyl orange indicator
`m" Eq of "H_(2)SO_(4)` used from the begining `=4.0xx0.05xx2`
`=4.0`
`a+b=4.0`
By equations (i) and (ii) we get
`a(m" Eq of "NaHCO_(3))=1.6`
Weight of `NaHCO_(3)=1.6xx10^(-3)xx84`
`=(0.1344g)/(30mL)`
`=(0.1344xx1000)/(30)gL^(-1)`
`=4.48 g L^(-1)`
`b(m" Eq of "Na_(2)CO_(3))=2.4`
Weight of `Na_(2)CO_(3)=2.4xx10^(-3)xx(106)/(2)`
`=(0.1272g)/(30mL)`
`=(0.1272xx1000)/(30)gL^(-1)`
`=4.24 g L^(-1)`
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY

    CENGAGE CHEMISTRY|Exercise Ex 3.6|10 Videos

  • STOICHIOMETRY

    CENGAGE CHEMISTRY|Exercise Ex 3.7|5 Videos

  • STOICHIOMETRY

    CENGAGE CHEMISTRY|Exercise Ex 3.4 (B)|18 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY|Exercise Exercises (Ture False)|25 Videos

  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Archives (Subjective)|23 Videos

Similar Questions

Explore conceptually related problems

A solution contains Na_(2)CO_(3) and NaHCO_(3). 10 mL of the solution required 2.5 mL "of" 0.1M H_(2)SO_(4) for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL "of" 0.2M H_(2)SO_(4) was required. The amount of Na_(2)CO_(3) and NaHCO_(3) in 1 "litre" of the solution is:

200 " mL of " a solution of a mixture of NaOH and Na_2CO_3 was first titrated with 0.1 M HCl using phenolphthalein indicator. 17.5 " mL of " HCl was required for the same HCl was again required for next end point. Find the amount of NaOH and Na_2CO_3 in the mixture.

0.1g of a solution containing Na_(2)CO_(3) and NaHCO_(3) requires 10mL of 0.01 N HCl for neutralization using phenolphthalein as an indicator, mass% of Na_(2)CO_(3) in solution is:

A mixutre solution of KOH and Na_2CO_3 requires 15 " mL of " (N)/(20) HCl when titrated with phenolphthalein as indicator.But the same amoound of the solutions when titrated with methyl orange as indicator requires 25 " mL of " the same acid. Calculate the amount of KOH and Na_2CO_3 present in the solution.