Calculate the percentage of oxalate ion in a given sample of oxalate salt of which 0.6 g dissolved 100 " mL of " water required 90 " mL of " `(M)/(100)KMnO_(4)` for complete oxidation.

Explanation

Mw of `C_(2)O_(4)^(2-)=88`
`Ew=(88)/(2)=44(n=2)`
`m" Eq of "C_(2)O_(4)^(2-)=m" Eq of "MnO_(4)^(ɵ)`
`(weightxx10^(3))/(44)=90xx(1)/(100)xx5`
Weight of `C_(2)O_(4)^(2-)=0.198g`
`% of C_(2)O_(4)^(2-)=(0.198xx100)/(0.6)=33%`