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20 " mL of " (M)/(60) KBrO3 was reacted ...

20 " mL of " `(M)/(60)` `KBrO_3` was reacted with a sample of `SeO_(3)^(2-)` 20 The `Br_(2)` thus evolved was removed and the excess of `NaAsO_(2)` The reaction involved are
`SeO_(3)^(2-)+BrO_(3)^(ɵ)+H^(o+)toSeO_(4)^(2-)+Br_(2)+H_(2)O` .. (i)
`BrO_(3)^(ɵ)+ASO_(2)^(ɵ)+H_(2)OtoBr^(ɵ)+AsO_(4)^(3-)+H^(o+)` ..(ii)
`[Mw(SeO_(3)^(2-))=79+48=127gmol^(-1)]`
Q. Which of the following is true (T) or false (F)?

A

Excess of m" Eq of "`BrO_(3)^(ɵ)=m" Eq of "AsO_(2)^(ɵ)` in reaction (ii)

B

`m" Eq of "SeO_(3)^(2-)=` otal m" Eq of "`BrO_(3)^(ɵ)`

C

`m" mol of "SeO_(3)^(2-)=` total m " mol of "`BrO_(3)^(ɵ)=` m" mol of "`BrO_(3)^(ɵ)` (excess) in reaction (ii).

D

m" Eq of "`SeO_(3)^(2-)=` total m" Eq of "`BrO_(3)^(ɵ)-m" Eq of "Bro_(3)^(ɵ)` (excess) usd in reaction (ii)

Text Solution

Verified by Experts

The correct Answer is:
A

(a). T.
(b). F.
(c). T.
(d). F.
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