A mixture of CO and `CO_(2)` when treated with `I_(2)O_(5)` gives `I_(2)` vapours accoeding to the following equation:
`5CO+I_(2)O_(5)to5CO_(2)+I_(2)`
`I_(2)` vapour was separated and treated with `HClO_(4)` and the resultant `HIO_(4)` required 0.001 " mol of "hlycerol for complete oxidation. After treatment with `I_(2)O_(5)` and removal of `I_(2)` ,t he mixture was treated with excess of 0.1 N NaOH solution and finally this solution required 20 " mL of " 1 N HCl to reach end point using phenolphthalein as indicator, followed by methyl orange as indicator after the first end point, 10 " mL of " further HCl was consumed.
Q. The number of moles of CO present initially is

Options

A. 0.001
B. 0.002
C. 0.005
D. 0.01

Answer

C

Explanation

`5CO+I_(2)O_(5)to5CO_(2)+I_(2)`
`I_(2)+2HClO_(4)to2HIO_(4)+Cl_(2)`
Number of moles of `HIO_(4)` required`=2xx0.001=0.002`
`underset(0.002)(2 " mol of "HIO_(4)=underset(0.001)(1 " mol of "I_(2))=underset(0.001xx5=0.005)(5 " mol of "CO)`
Number of moles of CO present initially`=0.005`