`H_2O_2` is reduced rapidly by `Sn^(2+). H_2O_2` is decomposed slowly at room temperature to yeild `O_2` and `H_2O`. `136g` of `10%` by mass of `H_2O_2` in water is treated with `100mL` of `3M Sn^(2+)` and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are:
`2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2)`
`2H_(2)O_(2)to2H_(2)O+O_(2)`
The volume strength of `H_2O_2` left after reacting with `Sn^(2+)`

Options

A. `1.12V`
B. `11.2V`
C. `2.24V`
D. `22.4V`

Answer

B

Explanation

`1 N of Eq L^(-1) of H_(2)O_(2)=5.6 volume of O_(2) at STP`
(Volume of strength of `H_(2)O_(2)`)
`impliesN=(0.2)/(100)xx1000=2EqL^(-1) of H_(2)O_(2)`
`=5.6xx2=11.2V`